Edexcel · GCSE Maths · 1MA1 · Foundation and Higher

M23 · Percentages and financial maths

Revision notes, worked examples and methods for percentages and financial maths.

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Revise the key ideas

Percentage change

  • A percentage means parts per hundred. To express A as a percentage of B, use × 100%, with B ≠ 0 and matching units.
  • For percentage change, use × 100%. The denominator is the original amount, not the new amount.
  • Worked example: A price rises from £40 to £46. Increase = £6 and percentage increase = × 100% = 15%.
  • An increase of p% multiplies by 1 + ; a decrease multiplies by 1 − . A 12% reduction uses multiplier 0.88.
    Forward and reverse percentage multipliersA twelve percent reduction multiplies two hundred fifty by zero point eight eight to give two hundred twenty. Dividing reverses it.£250× 0.88£220÷ 0.88 reverses the reduction
    Forward and reverse percentage multipliers
  • Worked example: £250 reduced by 12% becomes 250 × 0.88 = £220. Find the new amount directly with the multiplier.

Reverse percentages and repeated changes

  • Reverse a percentage change by dividing by its multiplier. A sale price of £72 after a 20% reduction came from 72 ÷ 0.8 = £90.
  • A 20% rise followed by a 20% fall is not no change: 1.2 × 0.8 = 0.96, giving an overall 4% decrease.
  • Simple interest is calculated on the original principal every year. At 4% simple interest, £500 earns £20 per year, so after 3 years the total is £560.
  • Compound interest applies the percentage to the changing balance. Final amount = P(1 + )n for n equal periods at rate r% per period.
  • Worked example: £500 at 4% compound interest for 3 years becomes 500 × 1.043 = £562.432, or £562.43 to the nearest penny. Round the final result, unless the account's rules specify rounding each year.
  • Depreciation or decay uses a multiplier below 1. A £12 000 car losing 15% of its value each year is worth 12 000 × 0.852 = £8670 after 2 years.
  • Rates and periods must match: an annual rate is not applied once per month without converting the model. State any assumption that the rate stays constant.

Higher — iterative financial models

  • If money is added or withdrawn each period, a simple power formula may no longer apply. Write a recurrence that reflects the order of interest and payments.
  • Worked example: A balance earns 2% interest, then receives a £100 deposit each year. Bₙ₊₁ = 1.02Bₙ + 100. Starting at £500 gives £610 after year 1 and £722.20 after year 2.
  • Depositing before interest instead gives Bₙ₊₁ = 1.02(Bₙ + 100), a different result. Use the wording to decide the order.
  • Find an unknown whole number of periods by repeated calculation or trial powers and check the first period at which the threshold is reached. Do not round a time up or down without interpreting the context.

Test yourself

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Practice questions with explained answers will be added here.

For now, cover the worked answers, try the calculations yourself, then compare each step. Include units and reasons where needed.

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