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Welcome to GCSE Edexcel Science revision.

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Unit C P 7: Energy ,  forces doing work.

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When a force moves an object through a distance in its direction, it transfers energy mechanically.

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This energy transfer is called work done and is measured in joules.

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For a constant force acting along the movement, work done equals force times distance moved in the direction of the force, E equals F times D.

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Use force in newtons and distance in metres; 1 joule equals 1 newton metres.

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Both force and displacement are along the same direction.

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Pushing a crate with 20 newtons through 3 metres in the force direction transfers 60 joules.

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Do not multiply by distance in an unrelated direction.

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If an object does not move, no mechanical work is done on it by the supporting force, even though a person's muscles may still transfer energy internally.

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A force at right angles to an object’s movement does no work on it.

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For example, the inward force on an object moving in a circle at constant speed changes its direction but not its speed.

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Work done against friction transfers energy to thermal stores of the surfaces and surroundings.

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This can be useful in brakes but unwanted in machinery.

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Measure force using a newton meter and displacement using a ruler or tape.

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A constant-force experiment needs the force direction aligned with the measured movement.

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Energy can be stored kinetically, thermally, chemically, gravitationally, elastically, magnetically, electrostatically or nuclearly.

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Transfer pathways include mechanical work, electrical transfer, heating and radiation.

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Energy is conserved: it cannot be created or destroyed.

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In a closed system, transfers move energy between stores or places, but the total stays the same.

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A motor lifting a load transfers energy electrically to the motor and mechanically to the load’s gravitational potential store.

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Some energy spreads to thermal stores in the surroundings (is dissipated).

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Useful gravitational energy plus unwanted transfers equals input energy.

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When a falling object speeds up, its gravitational potential store decreases while its kinetic store increases.

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Drag adds thermal transfers, so the kinetic gain may be smaller than the gravitational decrease.

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Dissipation spreads energy into less useful thermal stores; sound can carry energy away. “Wasted” describes usefulness for the task, not failure of conservation.

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Energy-flow diagrams identify input, useful output and unwanted transfers.

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For quantitative diagrams, the total output must equal input.

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Change in gravitational potential energy equals M times G times delta H.

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Use mass in kilograms, gravitational field strength in newtons per kilogram and vertical height change in metres to calculate energy in joules.

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A 5 kilograms mass raised 2 metres where G equals 10 newtons per kilogram gains 100 joules.

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The change depends on vertical rise, not the length of an inclined path.

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Kinetic energy equals one half times M times V squared, using mass in kilograms and speed in metres per second.

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Doubling mass doubles kinetic energy; doubling speed quadruples it.

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A 2 kilograms object at 4 metres per second has kinetic energy one half times 2 times 16 equals 16 joules.

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To find speed, rearrange V equals the square root of the quantity two times E divided by M.

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If all lost G P E becomes kinetic energy, M times G times delta H equals one half times M times V squared.

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The mass cancels; ignoring drag, the speed gained from a height depends on G and height.

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Conservation connects the two energy stores.

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To stop an object, its kinetic energy must be transferred.

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For a constant braking-force magnitude, F times D equals one half times M times V squared; larger speed increases required stopping distance strongly.

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For a load raised at constant speed, lifting force equals its weight and work done equals weight times vertical distance equals M times G times delta H.

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Acceleration or other losses may change input requirements.

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Power is the rate of energy transfer or work done: P equals E divided by T.

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Power is measured in watts; 1 watt equals 1 joule per second.

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A machine doing 600 joules of work in 3 seconds has power 200 watts.

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Two machines can do equal work but have different power if they take different times.

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Rearrange to E equals P times T and T equals E divided by P.

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Convert minutes to seconds and kilowatts to watts before using S I units.

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To investigate power while climbing stairs, measure mass, vertical height gained and time; calculate useful power equals M times G times delta H, divided by T.

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Use safe walking or running conditions and repeat.

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Use vertical height, not the sloping staircase length.

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To investigate lifting power, time raising a known weight through a measured vertical height.

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Control the load and height when comparing machines or people.

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Measured useful lifting power may be smaller than total input power because energy is also transferred to surroundings.

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State whether a calculation uses input or useful output.

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Efficiency equals useful energy output divided by total energy input.

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The same ratio applies to useful power divided by input power when comparing the same operating interval.

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Efficiency is a fraction from 0 to 1 or a percentage from 0 percent to 100 percent.

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A 60 percent efficient motor gives 60 joules useful output for every 100 joules input.

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Both examples have efficiency 60 percent; energy totals balance.

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Useful output equals efficiency fraction times input.

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Total input equals useful output divided by efficiency fraction; use 0.6 rather than 60 in these equations for 60 percent.

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Lubrication can reduce frictional heating.

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Insulation reduces unwanted heating of the surroundings; the improvement depends on the intended task.

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For a kettle, heating the water is useful, while heating the room is unwanted.

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For a lamp, light is useful while most heating is unwanted.

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Identify the task before classifying transfers.

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That completes Energy — forces doing work.

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Revisit the notes and test yourself on the revision website.
