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Welcome to GCSE Edexcel Science revision.

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Unit C P 13: Forces and matter.

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Stretching, compressing or bending an object involves more than one force, such as a pull at one end and a support force at the other.

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A single unopposed force can instead accelerate the object as a whole.

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Elastic deformation means an object returns to its original shape or length after the deforming forces are removed.

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Inelastic deformation leaves a permanent change.

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A spring can stretch elastically for small enough loads and become permanently deformed under a sufficiently large load.

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Elasticity is not a guarantee for every applied force.

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Different materials and shapes deform differently.

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A sheet may bend and spring back under a small force, but folding can leave a permanent crease.

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A rubber band can be elastic even though its force, extension graph is curved (non-linear).

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Extension X is stretched length minus original unstretched length.

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Compression is the reduction in length; equations below use the magnitude of deformation for a linear spring.

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Always subtract the original length before applying Hooke’s law.

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The elastic limit and limit of proportionality are different.

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Beyond the elastic limit, removing the force leaves a permanent change in shape or length.

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Beyond the limit of proportionality, the force, extension graph is no longer a straight line through the origin.

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For a spring in its linear range, force is proportional to extension: F equals K times X.

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This is Hooke’s law.

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F is in newtons, extension X in metres and spring constant K in newtons per metre.

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A larger spring constant means a stiffer spring: it needs a larger force for the same extension.

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K is not measured in newtons alone or in newton metres.

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Rearrange to K equals F divided by X and X equals F divided by K.

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Convert centimetres or millimetres to metres before finding K in newtons per metre.

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If 4 newtons extends a spring by 0.02 metres, K equals 4 divided by 0.02 equals 200 newtons per metre.

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In the same linear range, an 8 newtons load would give 0.04 metres extension.

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Greater load gives proportional extension only within the linear range.

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The spring's restoring force opposes deformation.

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A hanging load at rest is supported by a spring force equal to its weight; use F equals M times G to convert known mass to load force.

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Beyond the limit of proportionality, F is no longer directly proportional to X, so a single constant K cannot describe the whole curve using F equals K times X.

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For a Hooke’s-law spring, a force-versus-extension graph is a straight line through the origin.

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Force belongs on the vertical axis and extension on the horizontal axis for the rules here.

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Its gradient is the spring constant: K equals change in force divided by change in extension.

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A steeper line means a stiffer spring when the axes use the same units and scales.

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A curved (non-linear) graph means equal increases in force no longer give equal increases in extension.

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This does not necessarily mean the object is inelastic.

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Remove the force and check whether it returns to its original length.

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The limit of proportionality is where the graph first departs from its proportional straight-line behaviour.

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The elastic limit is where unloading starts leaving permanent deformation.

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Non-linear behaviour need not mean permanent deformation.

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If plotting extension against force instead, the gradient is one divided by K, not K.

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Always read the axes and units before using a gradient.

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A straight line that does not go through the origin may indicate a measurement offset or a different chosen length reference.

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Direct proportionality specifically requires the origin.

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Work done stretching or compressing a spring transfers energy into its elastic potential store.

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For an ideal elastic spring, energy can be returned as it relaxes.

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For a linear spring, E equals one half times K times X squared in joules, with K in newtons per metre and X in metres.

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The extension is squared; doubling extension quadruples energy at fixed K.

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A 200 newtons per metre spring extended by 0.02 metres stores one half times 200 times 0.02 squared equals 0.04 joules.

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The area under a force, extension graph represents work done.

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For a straight line through the origin, the triangular area is one half times F times X equals one half times K times X squared.

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Area equals one half times 4 times 0.02 equals 0.04 joules; final force times extension would be twice too large.

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Do not use final force times extension for a spring loaded from zero: force rises during stretching, so the average force is half the final force in the linear range.

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For a curved force, extension graph, find work done from the area under the graph if enough data are given.

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Do not use one half times K times X squared outside the straight-line range.

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Some work may heat the surroundings rather than being stored as elastic potential energy that can be recovered.

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Suspend a spring securely from a clamp stand beside a vertical ruler.

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Add a pointer if possible and record the unloaded length before adding masses.

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Add known masses in small steps, allow oscillations to settle and record length at eye level.

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Convert load mass to force using F equals M times G and calculate extension by subtracting unloaded length.

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Wait for oscillations to settle before measuring length.

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Keep the same spring, ruler position and attachment points.

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A fixed pointer and viewing at eye level reduce parallax; select a ruler resolution suitable for small extensions.

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Remove masses in steps as well and check whether the original length returns.

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Stop before damaging the spring unless specifically investigating its limits under supervision.

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Repeat readings and plot force against extension.

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Determine K from the linear gradient using two well-separated points on the best-fit line rather than a single noisy reading.

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Find work done from the graph area or one half times K times X squared within the linear range.

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Use metres rather than centimetres to get work in joules.

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Secure the stand against toppling, keep feet clear of falling masses and use eye protection where appropriate.

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Avoid overstretching the spring or leaving it oscillating while reading.

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That completes Forces and matter.

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Revisit the notes and test yourself on the revision website.
